Exponential Growth Calculator

Calculate growth or decay at a steady rate: the final amount, starting amount, rate or time, plus the doubling time.

Formula explained below

Find the

A negative rate is decay

In the same unit as the rate (years, days, hours)

Growth model

Result

1,628.894627

Total change
62.8895%
Doubling time or half-life
14.206699 periods to double
Growth factor per period
1.05

The amount after the time is shown above.

Calculation breakdown

Step-by-step calculation
StepFormulaResult
Result1,000 × (1 + 5%) ^ 101,628.894627

How it works

Choose what to find, then enter the other values. Time is in the same unit as the rate.

Per period: x(t) = x₀ × (1 + r)^tContinuous: x(t) = x₀ × e^(r t)Doubling time = ln 2 ÷ ln(1 + r)

Worked example

1,000 growing 5% a period for 10 periods:

  1. Growth factor per period: 1.05
  2. Final amount: 1,000 × 1.05^10 = 1,628.89
  3. Doubling time: ln 2 ÷ ln 1.05 = 14.2067 periods

Sources

Frequently asked questions

What is the exponential growth formula?

With a steady rate r per period, the amount after t periods is x₀ × (1 + r)^t. Starting with 1,000 and growing 5% a period for 10 periods gives 1,628.89. With continuous growth the formula is x₀ × e^(rt).

How do you find the doubling time?

Divide ln 2 by ln(1 + r). At 5% growth per period it takes about 14.2 periods to double. The calculator shows the doubling time, or the half-life when the rate is negative.

What is the difference between per-period and continuous growth?

Per-period growth applies the rate in steps, such as once a year. Continuous growth compounds at every instant, which gives a slightly larger result for the same rate, 1,648.72 against 1,628.89 after 10 periods at 5%.

How do I find the rate or the time?

Choose Rate or Time at the top. The rate is the (final ÷ start) to the power of 1 ÷ time, minus 1. The time is ln(final ÷ start) ÷ ln(1 + r).

Can I use this for decay?

Yes. Enter a negative rate, such as −10%. The amount shrinks each period, and the calculator shows the half-life.